~L-10,1000;FA71a~
F4
~{G; I530,850; X1.1; Y1.5; *FIGC1.PLT; X1.0; Y1.0;
I350,920; F9 {d}/{s} = 4
~I425,920; F9 {d}/{s} = 2
~I580,920; F9 {d}/{s} = .5
~I645,900; F9 {d}/{s} = .25
~I765,890; F9 {d}/{s} = 0
~L-650,50; FAFigure C1.~
M1NGB25;
L-450,50;F1Log magnitude frequency response of digital resonator-antiresonator,~
L-450,20;F1plotted for {d}/{s} = 4, 2, 1, .5, .25,  and 0.~

I1530,850; X1.1; Y1.5; *FIGC2.PLT; X1.0; Y1.0;
I1500,820; F9 G = .25
~I1550,820; F9 G = .5
~I1650,800; F9 G = .75
~I1750,780; F9 G = 1.0
~L-650,-850; FAFigure C2.~
L-450,-850;F1Magnitude frequency response of all-zero comb filter with values  of  gain G = .25, .5,~
L-450,-880;F1.75, and 1.0. Zeros of transmission are at integral multiples of 400 Hz.
~~L-10,1000;FA71b~
I530,850; X1.1; Y1.5; *FIGC3.PLT; X1.0; Y1.0;
I345,780; F9 G = 1.0
~I445,800; F9 G = .75
~I545,820; F9 G = .5
~I595,820; F9 G = .25
~L-650,-50; FAFigure C3.~
L-450,-50;F1Log magnitude frequency response of comb filter used as harmonic resonator with poles~
L-450,-80;F1at integral multiples of 400 Hz. Four values of gain, G, are shown. They are G = .25, .5,~
L-450,-110;F1.75, and 1.0
~~L-10,1000;FA65a~
I530,850; X1.1; Y1.5; *FIGA1.PLT; X1.0; Y1.0;
L-650,50; FAFigure A1.~
L-450,50;F1Log magnitude frequency response of the heterodyne filter for a base frequency of~
L-450,20;F1125 Hz and j=4. There is a zero of transmission at every multiple of 125 Hz except~
L-450,-10;F1the fourth one.